Monday, April 16, 2012

Elemental analysis of the unknown gas from Part A revealed that it is 30.45 and 69.55 . What is the molecular formula for this gas?


Elemental analysis of the unknown gas from Part A revealed that it is 30.45\% \rm N and 69.55\% \rm O. What is the molecular formula for this gas?
Express your answer as a chemical formula.
\rm{N_{2}O_{4}}
Correct

1 comments:

  1. N2O4 you multiply the percent's by your mass percent, divide by molar mass and then there's your answer no need to simplify.

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